Earlier today Republican Presidential candidate Ron Paul defeated his
GOP competitors, winning 82 percent of the vote in a poll of Iowa GOP
activists. Dr. Paul's nearest competitor was pizza baron Herman Cain,
who garnered an unimpressive 14.7 percent of the vote.
The poll of Iowa voters took place in Des Moines as part of the National
Federation of Republic Assemblies Presidential Preference Convention and
Straw Poll. The victory among Iowa voters demonstrates that Dr. Paul has
substantial support among Republican Party activists in the Hawkeye
"In Iowa, Ron Paul continues to engage and inspire concerned voters at
town hall meetings and in other settings. This contest, however, shows
that Dr. Paul and his campaign have tremendous organization strength.
Iowa voters are ready for when the opportunity to vote for Ron Paul
arises, and today they have done just that quite decisively," said Ron
Paul 2012 National Campaign Chairman Jesse Benton.
In addition to winning the Iowa-only tally conducted at the NFRA
convention, Dr. Paul won the open-voter tally which was not restricted
to voters from Iowa. The open-voter results had Dr. Paul winning by 26
percent, followed by Cain at 25 percent, Perry and Santorum tied at 16
percent, and others with low double- and single-digit percentages.
Below find the straw poll results for the Iowa-only contest:
Ron Paul 82%.
Herman Cain 14.7%
Rick Santorum 1%
Newt Gingrich 0.9%
Michele Bachmann 0.5%
Rick Perry 0.5%
Gary Johnson 0.2%
Mitt Romney 0%
Jon Huntsman 0%
Authorized and paid for by Ron Paul 2012 PCC Inc. www.RonPaul2012.com